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form23.frm
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1999-05-05
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VERSION 5.00
Begin VB.Form Form1
Caption = "Form1"
ClientHeight = 3525
ClientLeft = 60
ClientTop = 345
ClientWidth = 5175
LinkTopic = "Form1"
ScaleHeight = 3525
ScaleWidth = 5175
StartUpPosition = 3 'Windows Default
Begin VB.TextBox Text2
Height = 495
Left = 1680
TabIndex = 5
Text = "ashaMuralidhar"
Top = 360
Width = 1815
End
Begin VB.CommandButton Command2
Caption = "Close"
Height = 495
Left = 3360
TabIndex = 4
Top = 2760
Width = 1215
End
Begin VB.CommandButton Command1
Caption = "Find"
Height = 495
Left = 1800
TabIndex = 1
Top = 1800
Width = 1455
End
Begin VB.TextBox Text1
Height = 495
Left = 1920
TabIndex = 0
Top = 1080
Width = 1215
End
Begin VB.Label Label2
Caption = "Main String"
Height = 375
Left = 600
TabIndex = 3
Top = 360
Width = 1095
End
Begin VB.Label Label1
Caption = "Find string"
Height = 375
Left = 720
TabIndex = 2
Top = 1080
Width = 975
End
End
Attribute VB_Name = "Form1"
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = False
Attribute VB_PredeclaredId = True
Attribute VB_Exposed = False
Option Explicit
Dim Pos As Integer, temp As String, ctr As Integer
Private Sub Command1_Click()
' Counts the number of occurances of the string
ctr = 0
' gives the position aof the string
Pos = 0
If Len(Text1.Text) = 0 Then
MsgBox "Enter String to be found"
Else
If Len(Text2.Text) = 0 Then
MsgBox "Enter String to be searched in"
Else
temp = Text2.Text ' temporary variable
' the loop sees if there are more than one occurance of a string/words in a string
Do
Pos = InStr(temp, Text1.Text) 'finds the substring in the string
If Pos = 0 Then ' string not found in main string
Exit Do
End If
ctr = ctr + 1 ' count the number of occurances
temp = Right(temp, Len(temp) - Pos)
Loop While (ctr > 0 And Len(temp) > Len(Text1.Text))
MsgBox ctr ' displays the number of occurances
End If
End If
End Sub
Private Sub Command2_Click()
Unload Me
End Sub